a two digit number such that the sum of digit 6 . if the digits of the number are reversed , the number gets deminished by 18.find the orginal number.
plzzzzzzzzzzzzzzzzzzzzzzzz anyone give the answer plzzzzzzzzzzzzzzzz
plzzzzzzzzzzzzz
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Let the tenth (place) digit of the original number be x and unit digit be y.so original number would be,
10x+y.
when digits are reversed,new number would be,
x+10y.
10x+y=x+10y+18.
x-y=2 -------- first equation.
but sum is,
x+y=6............ second equation.
add two equations.we get,
2x=8.
x=4.
y=2.
therefore the original number is 42.
10x+y.
when digits are reversed,new number would be,
x+10y.
10x+y=x+10y+18.
x-y=2 -------- first equation.
but sum is,
x+y=6............ second equation.
add two equations.we get,
2x=8.
x=4.
y=2.
therefore the original number is 42.
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