Question

A two digit number when divided by the sum of the digits and the quotient becomes 6 and a remainder 7 but when the digits are interchanged in position and on being divided by the same sum the quotient becomes 4 and remainder 6 what is the original number

Answer 1

Step-by-step explanation:

the value of tenth place digit is5÷6=0.8

the value of unit place digit is 11÷6=3.6

so, the number is 10*0.8+3.6=11.6