Question

a two digit number whose digits make the sum of the square of its lowest number. if reverse we get a multiple of 8. what is the number??? I bet u can't do in 1st attempt.​

Answer 1

Answer:

42

Step-by-step explanation:

Let the number at one's place be x, then the number at tens place will become x²

Number formed =

T O

X² X

We can write the number as X²*10+x

= 10X² x

When number reversed =

10x x²

Their difference = 18

10x² + x - (10x + x²) = 18

10x² + x - 10x - x² = 18

9x² - 9x - 18 = 0

9x² - 18x + 9x - 18 =0

9x(x - 2) +9(x - 2) = 0

(9x+ 9) (x - 2) = 0

x = - 1 and x = 2

Digits of a number are always positive thus 2 is the value of x

Number will be 42

When reversed = 24

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Done in first attempt only.