Question

A two digit number whose sum of digits is 12 has a difference of 18 with the number with the digits reversed. The number is?

With step by step explanation ​

Answer 1

Answer:

Let the tens digit of the required number be x and the units digit be y. Then,

x+y=12 .........(1)

Required Number = (10x+y).

Number obtained on reversing the digits = (10y+x).

Therefore,

(10y+x)−(10x+y)=18

9y−9x=18

y−x=2 ..........(2)

On adding (1) and (2), we get,

2y=14⟹y=7

Therefore,

x=5

Hence, the required number is 57.

Answer 2

let the digit in the number is x y

so number is 10x + y

given

sum of the digits of a two digit number is 12

= x+y =12

again

10y + x = 10x + y +18

10y + x - 10x - y =18

9y - 9x = 18

y- x = 2

solving equation 1 and 2, we get

x=5 , y=7

so the number is 57

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