Question

a two digit number whose unit digit is(a+b)and tens digit (a-b) is______. (a) 9a-11b (b) 9a+11b (c) 11a+9b (d) 11a-9b​

Answer 1

Answer:

11a - 9b

Step-by-step explanation:

units digit = a+b

tens digit = a-b

(a+b)1 + (a-b)10 = a + b + 10a - 10b

= 11a - 9b

Answer 2

Step-by-step explanation:

Given:a two digit number whose unit digit is(a+b)and tens digit (a-b) is______.

To find: Fill in the blank

(a) 9a-11b

(b) 9a+11b

(c) 11a+9b

(d) 11a-9b

Solution:

Tip: Remember that in expanded form one can write 85 as 80+5

That means,Tens digit should multiply with 10.

Here

Unit digit is : a+b

it will remain same.

Tens digit is: a-b

it should be multiply by 10

So,

10(a-b)

or

Tens digit is:10a-10b

Now,the number will be

$= > 10a - 10b + a + b \\ \\ = > 10a + a - 10b + b \\ \\ = >\bold{\red{ 11a - 9b}}$

Final answer:

Option D is correct.

Hope it helps you.

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