A two-
-digit numbert is 4 times the sum of its digits)
if 18 is added to the number the digits
digits
are refer-
sed, find the number.
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Answer:
Let unit's digit =y and the ten's digit =x
So, the original number =10x+y
The sum of the two digit number =10x+y
The sum of the digit =x+y
According to the question, (10x+y)=4(x+y)
⇒10x+y=4x+4y
⇒10x−4x+y−4y=0
⇒6x−3y=0
⇒2x−y=0
⇒y=2x….(i)
After interchanging the digits,
New number =x+10y and 10x+y+18=x+10y
⇒10x+y+18=x+10y
⇒10x−x+y−10y=−18
⇒9x−9y=−18
⇒x−y=−2…(ii)
On substituting the value of y=2x in Eq. (ii),we get
x−y=−2
⇒x−2x=−2
⇒−x=−2
⇒x=2
On putting the value of x=2 in Eq. (i), we get
y=2×2=4
So, the Original number =10x+y
=10×2+4
=20+4
=24
Hence, the two digit number is 24.
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