Math, asked by akanshashukla2003, 4 months ago

A two digit positive number is such that the product of the digits is 4 and if 27 is added to the number, digits interchange there place​

Answers

Answered by Anonymous
2

Answer:

ANSWER

Let the required two digit number be 10x+y

Given: xy=6 and 10x+y+9=10y+x

10x−x+y−10y+9=0

⇒9x−9y+9=0

⇒x−y+1=0

⇒y=x+1

∵xy=6 (given)

⇒x(x+1)=6

⇒x2+x−6=0

⇒x2+3x−2x−6=0

⇒(x+3)(x−2)=0

Rejecting x=−3

When x=2,y=x+1=2+1=3

∴ The required two digit number =10x+y

=10×2+3

=23

hope this helps you mate

please mark me brainliest ✌❤

Similar questions