A two dignumber is obtained by either multiplying the sum of the digits by 8 and then subtracting
5 or by multiplying the difference of the digits by 16 and then adding 3. Find the number. (83)
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Answer:
Number-83
Step-by-step explanation:
Let the tenth's digit be x and one's digit be y.
Then the number is 10x+y.
By the first condition-
(x+y)×8−5=10x+y
⇒2x−7y=−5 ........(i)
By the second condition-
(x−y)×16+3=10x+y
⇒6x−17y=−3 ..........(ii)
Multiplying (i) by 3, we get
6x−21y=−15 .......(iii)
Subtracting (ii) from (iii), we get
−4y=−12
⇒y=3.
Substituting y=3 in (i)
2x−7×3=−5
⇒x=8
∴ The number is 10×8+3=83.
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