A two dijit number is such that twice the tens dijit is three less than the ones dijit.Given also that the product of the dijits is three more than twice the sum of the dijits . Find the number
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Let the number be xy
2x=y-3
x*y=3+2*(x+y)
putting y=2x+3
2x²+3x=3+6x+6
2x²-3x-9=0
2x²-6x+3x-9=0
(2x+3)(x-3)=0
Digits aren't fractional
Sp x=3
y=9
number 39
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