Question

A two dijit number is such that twice the tens dijit is three less than the ones dijit.Given also that the product of the dijits is three more than twice the sum of the dijits . Find the number​

Answer 1

Let the number be xy

2x=y-3

x*y=3+2*(x+y)

putting y=2x+3

2x²+3x=3+6x+6

2x²-3x-9=0

2x²-6x+3x-9=0

(2x+3)(x-3)=0

Digits aren't fractional

Sp x=3

y=9

number 39

Step-by-step explanation:

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