(a) Two lenses have powers of (i) + 2D and (ii) -4D. What are the nature and focal length of each lens? (b) An object is kept at a distance of 100 cm from each of the above lenses. Calculate the (i) image distance and (ii) magnification in each of the two cases.
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Answer:
given = 2 Lenses have power +2D and -4D
to find = distance and magnification in both cases.
solution :-
focal length = 100/2 cm = 50
the lenses is convex lens of focal length =50cm
the focal length = 100/p = 100/-4= -25
now,
for power of lenses +2D
u= -100 , f =+50
v=?
use the lense formula ,
1/f = 1/v-1/u
1/v = 1/40 -1/100
1/v = 60/4000
1/v= 400/6 =66.6 cm
magnification = m = -v/u
= -66.6/100
m= 0.66
now, for power of lenses -4D
1/f =1/v-1/u
1/v = 1/f +1/u
1/v = 1/--25 - 1/100
1/v= -125/2500
v= -2500/125
v2= -20cm
mqgnification = -v/u
m = -(-20/-100)
m= -1/5
m= 0.2
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