Question

a) Two resistances of 4 Ω and 8 Ω are connected in parallel. What would be the combined
resistance of the system?
b) Two identical resistors each of resistance 2 Ohm are connected in turn (1) in series (2) in
parallel to a battery of 12 V. Calculate the ratio of power consumed in two case

Answer 1

Answer:

a) 2.666666666666666666666666666666666666666666666

b)Potential Difference(V) = 12V

Current(I)= V/R

              =12/4

              =3Ampere

Power = VI

          = 12*3

          =36 Watts

(2) IN PARALLEL

 1/R₁ + 1/R₂ = 1/Rₐ (Where Rₐ is the total resistance)

 1/2 + 1/2 = 1/Rₐ                                            

 2/2 =1/Rₐ

 1/1 = 1/Rₐ       

 1 Ohm = Rₐ

Voltage (V)= 12Volts

Current(I)= V/R

              = 12 Ampere

Power= VI

         = 12*12

         = 144 Watt

Power in series : Power in Parallel

36 : 144

1 : 4

Click to let others know, how helpful is it

mark me as brainliest

XD

Answer 2

Hope this will help.....

Please mark as brainliest.... &.... Follow....