Physics, asked by saku8024, 7 months ago

(a) Two resistors of resistance R, = (
40.5) Q and R= (16 40.5) are connected (I) in series (II) in parallel
Find the equivalent resistance in each case,

(b) The percentage errors in the measurement of mass and speed are 2% and 3% respectively.
How much will be the maximum percentage error in the chimation of kinetic energy obtained by measuring
mass and speed

Answers

Answered by PrasadMaity
0

Answer:

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Answered by Anonymous
1

Answer:

Sorry but I don't have a clue about the a) one

b) Given percentage errors in mass and velocity = 2% and 3% respectively

The kinetic energy of the particle is given by

KE =mv²/2

The percentage error in kinetic energy will be

m/Δm×100+2vΔ/v×100

= 2+6

= 8%

This is your answer mate

Hope this helps you!

Purple you!!

Have a great day ahead!!

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