(a) Two tuning forks A and B produce 4 beats per second. On loading B with wax 6 beats are produced. If the quantity of wax is reduced the number of beats drops to 4. If the frequency of A is 326 Hz, find the frequency of B.
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Since four beats per second are heard when A and B are sounded together, 256Hz−ν=±4Hz
where ν is the frequency of B.
Now, loading with wax decreases the frequency of tuning fork.
Waxing tuning fork A would mean the frequency of A has reduced such a way that it again produces 4 beats per second with B. Thus it is now lower than B by 4Hz and initially it was higher than B by 4Hz.
⟹256Hz−ν=4Hz
⟹ν=252Hz
Explanation:
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