Math, asked by singhvishalkumar824, 11 months ago

A tyre manufacturing company kept a record of the distance covered before a tyre needed to be replaced. The table shows the results of 1000 cases.

(Distance (in km) - Frequency)

Less than 4000 - 20

4000 to 9000 - 210

9001 to 14000 - 325

More than 14000 - 445

If you buy a tyre of this company, what is the probability that(i) it will need to be replaced before it has covered 4000 km ? (ii) it will be replaced after 9000 km ?(iii) it will need to be replaced after it has covered distance somewhere between 4000 km and 14000 km ?

Answers

Answered by jenil177
62

Answer:

(1) 20/1000=0.02

(2)770/1000=0.77

(3)535/1000=0.535

It is by formula

Number of trial/total number of trial

Answered by DarkPsycho
82

(i) 20 tyres need to be replaced before 4000 km out of 1000 tyres.

probability that the tyre needs to be replaced before covering 4000 km = 20/1000 = 0.02 or 2%

(ii) tyres replaced after 9000 km = 325+445 = 770 tyres out of 1000

probability = 770/1000 = 0.77 or 77%

(iii) tyres replaced between 4000 and 14000 km = 325+210+20 = 555 tyres out of 1000

probability = 555/1000 = 0.555 or 55.5%

I have used:

probability = \frac{number of desired outcome}{total number of outcomes}

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