Question

A tyre pumped to a pressure of 3.375 atmosphere and at 27°C suddenly bursts.caculate the temperature of escaping air.given γ = 1.5.

Answer 1

Hey Mate..

T1γ P1 γ − 1 = T2γ P2γ − 1

⇒ ( 300T2 ) 3/2 = (3.3751) 1/2  

T2 = 300 (3.375)

1/3 = 200K

= −73∘C

Thank You..

Answer 2

Hey mate ^ _^

Solution _________

• The temperature of escaping air is :-

____
_________

T1 y P1 y - 1 = T2 y P2 y - 1

( 300 T2 ) 3/2 = ( 3.3751) 1/2

T2 = 300(3.75)

1/3 = 200 K

Into Celsius it will be.... 73°C...

Thank you