Question

A tyre pumped to a pressure of 3 atmosphere suddenly bursts.

Calculate the fall in temperature if the temperature of air before

expansion is 27oC and γ = 1.4.

Answer 1



Abhay Kumar answered this

PV^gamma = constant.
 PV =nRT,
P*(nRT/P)^gamma = constant.
(P^1-gamma)*(T)^gamma = constant.
T=300 K and P = 3 atm
for P= 1 atm as initial and final pressure of tyre is the same!
Get T
T =219.19 K so dt=80.2 K or C.
Thus the temperature is decreased

Answer 2

Answer:

Explanation:

Abhay Kumar answered this

PV^gamma = constant.

 PV =nRT,

P*(nRT/P)^gamma = constant.

(P^1-gamma)*(T)^gamma = constant.

T=300 K and P = 3 atm

for P= 1 atm as initial and final pressure of tyre is the same!

Get T

T =219.19 K so dt=80.2 K or C.

Thus the temperature is decreased

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