A U-shaped wire is dipped in a soap solution, and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 x 10⁻² N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?
Answers
Answered by
10
Hey mate :-)
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Answer:
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W = 1.5 × 10^–2 N
l = 30 cm = 0.3 m
Total length = 2l = 2 × 0.3 = 0.6 m
S (Surface tension) = Force or Weight / 2l
= 1.5 × 10^-2 / 0.6
= 2.5 × 10^-2 N/m
Final answer: 2.5 × 10^–2 N m^–1
#Be Brainly❤️
=======
Answer:
=======
W = 1.5 × 10^–2 N
l = 30 cm = 0.3 m
Total length = 2l = 2 × 0.3 = 0.6 m
S (Surface tension) = Force or Weight / 2l
= 1.5 × 10^-2 / 0.6
= 2.5 × 10^-2 N/m
Final answer: 2.5 × 10^–2 N m^–1
#Be Brainly❤️
Brainlytrainer:
answer my question you got 25 marks
Answered by
1
Answer:
Explanation:
Length of the slider ( L) = 30cm
We know,
A soap film has two free surface , therefore total length of the film to be supported
L" = 2L = 2×30 = 60 cm
Let s is the surface tension of the soap .
Total force on the slider due to surface tension
F = S× L"
= S × (60 cm)
= S × 0.6 N
Weight Supported by slider (w) = 1.5 × 10^-2 N
In equilibrium condition,
Force due to surface tension = weight supported by slider
F = w
S × 0.6 = 1.5 × 10^-2
S = 1.5 × 10^-2/0.6
= 2.5 × 10^-2 N/m
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