Question

A U tube is first partially filled with mercury. Then water is added in one arm and an oil is added in the other arm. Find the ratio of water and oil columns so that mercury level is same in both the arms of U tube Given density of water = 10 kgm derisity of ol 900kgms 3 6 10​

Answer 1

Answer:

U tube is first partially filled with mercury. Then water is added in one arm and an oil is added in the other arm. Find the ratio of water and oil columns so that mercury level is same in both the arms of U tube Given density of water = 10 kgm derisity of ol 900kgms 3 6 10

Answer 2

Answer:

Explanation:

Liquid

SOLUTION

Since the level of mercury in the two arms of the U-tube is same, therefore,

Pressure exerted by water columnin one arm =pressure exerted by liquid column in other arm

i.e., hidig = had2g

hi_

d2

+

hz

900 kgm-3

1000 kgm-3

10

Hence, the ratio of lengths of water and the liquid is 9 : 10.