A u-tube is partially filled with water. Oil, which does not mix with water, is next poured into one side until water rises by 25 cm on the other side. If the density of oil be 0.8, the oil level will stand higher than the water level by:
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15
Answer:
The answer will be 12.5 cm
Explanation:
According to the problem the oil is poured into until the height of the water level rises 25 cm on one side from its initial height
Therefore the height will decrease with 25 cm in another side
It is given that the density of the oil is 0.8 g /cm^3
Let the oil level stands h cm higher .
let two point at same distance in the tube at same level pressure will be same
Therefore p1 = p2
p0 +ρ0 g(h+25+25) = po + ρw g hw
=> ρ(oil) x(h+50) = ρ(water)x 50 [ρ(water = 1]
=> 0.8 (h+50) = 1 x 50
=> h = 12.5 cm
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