A U - tube of base length "L" filled with same volume of two liquids of densities p and 2p is moving
with an acceleration "a" on the horizontal plane. If the height difference between the two surfaces
(open to atmosphere) becomes zero, then the height h is given by :
Answers
Answered by
3
The height "h" is given by h = 3La/2g
Explanation:
According to the question liquid of density "2ρ" should be behind that of "ρ" .
P(A) = P(atm) + ρgh
P(B) = P(A) + ρLa/2
= P(atm) + ρgh + ρLa/2
P(C) = P(B) + 2ρLa/2
= P(atm) + ρgh + ρLa/2 + ρLa
= P(atm) + ρgh + 3ρLa/2
Also, P(C) = P(atm) + 2ρgh
P(atm) + ρgh + 3ρLa/2 = P(atm) + 2ρgh
After cancellation:
3ρLa/2 = ρgh
h = 3La/2g
thus the height "h" is given by h = 3La/2g
Learn more about
What is density ?
https://brainly.in/question/8278335
Similar questions