Question

A uniform, 453 g metal bar 76.0 cm long carries a current I in a uniform, horizontal 1.75 T magnetic field as shown in the following figure. The directions of I and B⃗ are shown in the figure. The bar is free to rotate about a frictionless hinge at point b. The other end of the bar rests on a conducting support at point a but is not attached there. The bar rests at an angle 60.0 ∘ of above the horizontal.(Figure 1)

Answer 1

Answer:

Thanks

Explanation:

For your sample question

Answer 2

The current is 1.66 A.

Explanation:

Given that,

Mass = 453 g

Length = 76.0 cm

Magnetic field  = 1.75 T

Suppose we need to calculate the largest value the current I can have without breaking the electrical contact at a

We need to calculate the current

Using formula of magnetic force

$F_{B}=mg\cos60$

$BIL=mg\cos60$

$I=\dfrac{mg\cos60}{BL}$

Put the value into the formula

$I=\dfrac{453\times10^{-3}\times9.8\cos60}{1.75\times76.0\times10^{-3}}$

$I=1.66\ A$

Hence,  The current is 1.66 A.

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Topic : magnetic force

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