Question

A uniform bar 3.00 m long is held by ropes at the ends making angle 60.0 and 30.0, respectively, with the horizontal. A weight of 200 N is hung 0.500 m from the left end where the 60.0 rope is attached. Find the tension in the ropes (T1 & T2) and the weight (W) of the bar. (Hint: Formulate three equations for the three unknowns, 2 equations for the 1st condition and 1 equation for the 2nd condition.)

Answer 1

Answer:

W+200=T

1

sin60+T

2

sin30

T

1

cos60=T

2

cos30

200(1)=T

1

(1.5)sin60−T

2

(1.5)sin30

T_1=231\ N\\T_2=133\ N\\ W=67\ NT

1

=231 N

T

2

=133 N

W=67 N