A uniform bar length of 1.0m is supported 30cm from one end. In order to balance the bar, a weight of 10N is glued on the end. What is the weight of the bar?
explaination required....
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Answered by
6
Answer:
Explanation:
Let weight of bar be x
Clockwise moment=anticlockwise moment
=>X × (50-30)=10N×30
=>X=((10×30)/20)N
=>X=15N
The weight of the bar is 15N
Answered by
0
Explanation:
clocke wise torque= anticloxkwise torque
X(70-30)=10x30
X=7.5N
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