Physics, asked by babazbiba06, 11 months ago

A uniform bar length of 1.0m is supported 30cm from one end. In order to balance the bar, a weight of 10N is glued on the end. What is the weight of the bar?
explaination required....

Answers

Answered by pratibhanayak30
6

Answer:

Explanation:

Let weight of bar be x

Clockwise moment=anticlockwise moment

=>X × (50-30)=10N×30

=>X=((10×30)/20)N

=>X=15N

The weight of the bar is 15N

Answered by aaabbb194
0

Explanation:

clocke wise torque= anticloxkwise torque

X(70-30)=10x30

X=7.5N

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