Question

A uniform beam 6 meters long and weighing 4kg rest on supports at P&Q placed left and right 1 metre from each end of the beam. Weights 10kg & 8kg are placed near P&Q respectively one each end of the beam. Calculate the reactions of P&Q

Answer 1

p and q are 4.0 m apart

moments around q

4 p = (10 * 5) + (4 * 2) - (8 * 1)

p = 12.5

Rp = 12.5 g

moments around p

4 q = (8 * 5) * (4 * 2) - (10 * 1)

q = 9.5

Rq = 9.5 g:

Hope it helps...