Question

A uniform beam 6m long and weighing 40N rests on supports at P and Q placed left and right 1m from each end of the beam. Weights of 100N and 80N are placed near P and Q respectively on each end of the beam, calculate the reaction at P and Q.

Answer 1

Explanation:

p and q are 4.0 m apart

moments around q

4 p = (10 * 5) + (4 * 2) - (8 * 1)

p = 12.5

Rp = 12.5 g

moments around p

4 q = (8 * 5) * (4 * 2) - (10 * 1)

q = 9.5

Rq = 9.5 g

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