A uniform beam is pivoted at P as shown. Weights of 10 N and 20N are attached to its ends.
The length of the beam is marked at 0.1 m intervals. The weight of the beam is 100N.
At which point should a further weight of 20 N be attached to achieve equilibrium?
0.4 m
0.6 m
0.1 m
С
A
P
20N
10N
Answers
Answer:
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Head injuries.
Severe injuries to the upper part of the nose.
Severe upper respiratory infections.
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Inhaling certain chemicals such as pesticides or ammonia for long periods of time (years)
Hormonal imbalances.
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Head injuries.
Severe injuries to the upper part of the nose.
Severe upper respiratory infections.
Polyps in the sinus cavities or nasal passages.
Tobacco smoke.
Inhaling certain chemicals such as pesticides or ammonia for long periods of time (years)
Hormonal imbalances.
Answer:
option D
Explanation:
Since the beam is uniform, its weight acts at the centre, that is, 0.1m to the left of P (where B is).
For equilibrium, the sum of clockwise moment should be equal to the sum of anticlockwise moment.
Clockwise moment = 20(0.4) Nm
Anticlockwise moment = 10(0.6) + 100(0.1) Nm
Since the anticlockwise moment is greater, the further weight of 20N should contribute to the sum of clockwise moments. That is, it should be to the right of P. Let the position of the further weight of 20N be x to the right of P.
Sum of clockwise moment = Sum of anticlockwise moment
20(0.4) + 20(x) = 100(0.1) + 10(0.6)
Position x = 0.4m