Physics, asked by zainabdottbutt, 8 months ago

a uniform beam of 200N is supported horizontally.if the breaking tension of the rope is 400N how far can block B of weight 400N from point A on the beam?

Answers

Answered by manetho
0

Explanation:

Considering the beam supported by a pivot at A and the rope at B. In that case the beam applies a load of 100 N on the rope. This means the man can walk out until he applies a load of 300 N on the rope end. At that point the rope would break. 300 N is 3/4 of 400 N so he can walk 3/4 of the way from A to B.

Answered by hiraschoolandcollege
0

Answer:

4 A uniform beam of 200 N is supported horizontally as shown in fig.2.27 (a). If the breaking tension of the rope is 400 N, how far can a man of weight 400 N walk from A to B on the beam.

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