a uniform beam of length l and mass m is equals to 1.8 kg rests with its end on two digital scales.A uniform block whose mass is equals to 2.7 kg rests on the beam.its centre being at the distance l/4 from the beam left end. What do the scales read
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Let the Force experienced by left scale is F(L) and by right if F(R)
=>F(L) + F(R) = 2.7g + 1.8g
=>F(L) + F(R) = 4.5g --------------------(i)
By taking torque at center:-
=>F(L) x L/2 = F(R) x L/2 + 2.7g x L/4
=>F(L) = F(R) + 1.35g --------------(ii)
=>BY(i):-
=>F(R) + 1.35g + F(R) = 4.5g
=>F(R) = 1.58g = 1.58 x 9.8 = 15.44 Newton
BY (ii) :-F(L) = 2.93g = 28.67 Newton
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