A uniform beam of weight 50N is 3m long and is supported on a pivot situated 1m from
one end. When a load of weight w is hung from that end. The beam is in equilibrium, what
is value of w?
b. 50N
d. 100N
La. 25N
c 75N
Answers
Answered by
5
Answer:
For equilibrium , net torque = 0
Taking clockwise direction positive,
W×(−1)+50kN×0.5=0
⟹−W=−50kN×0.5
⟹−W=−25kN
⟹W=25kN
Answered by
0
Answer:
a) option is the correct option
Similar questions