A uniform box of height 2m & having a square base of side 1m , weight 150 kg ,is kept on end of the floor of the truck , the maximum speed with which the truck can round the curve of radius 20 m without causing the block to tip over is
A) 15 m/s
B) 10 m/s
C) 8 m/s
D) Data Depend upon the co eff of friction
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Answer:
data depend upon the co eff of friction
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Answer:
10 m/s.
Explanation:
As the block is moving in the curved path so there will be net force of centripetal which will be mv^2/r where r is the radius of the curve and v is the velocity of the box. So, the force will be normal * perpendicular distance, here the perpendicular distance will be half of the side of the square.
So, N*0.5 = mv^2/r where N is mg. Hence, 0.5mg=mv^2/20 or 0.5*10=v^2/20 which on solving we will get the value of v to be 10 m/s.
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