Question

A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface such that its (1/n)th part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be :
(A) nMgL (B) MgL/2n²
(C) 2MgL/n²
(D) MgL/n²

Answer 1

hi mate....♥

A uniform cable of mass M and length L is placed on a horizontal surface such that its

1/n th parth is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be:

a) MgL/n²

b) MgL/2n²

c) 2MgL/n²

d) nMgL

hope it was helpful ♥