Question

A uniform chain of length 2 m is kept on a table such that a length of 60cm hangs freely from edge of table. The total mass of the chain is 4 kg. What is the work done by a force parallel to the horizontal surface in pulling the entire chain slowly on the table?

Answer 1

l and m are length and mass of part of chain hanging down .

M and L are total lenght and mass of the chain.

M = 4 kg

L = 2 m

l = 0.6 m

m = l / L * 4 = (0.6 / 2) * 4 = 1.2 kg

Tension in chain hanging down = mg = 12 N (g=10 m/s^2)

Force required = Tension

Displacement = 0.6 m (part of chain hanging comes up)

W= Force * Displacement = 12 * 0.6 = 7.2 J

WORK DONE = 7.2 J.

Answer 2

HEY MATE HERE IS YOUR ANSWER IN ATTACHMENT