A uniform chain of length 2 m is kept on a table such that a length of 60cm hangs freely from edge of table. The total mass of the chain is 4 kg. What is the work done by a force parallel to the horizontal surface in pulling the entire chain slowly on the table?
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l and m are length and mass of part of chain hanging down .
M and L are total lenght and mass of the chain.
M = 4 kg
L = 2 m
l = 0.6 m
m = l / L * 4 = (0.6 / 2) * 4 = 1.2 kg
Tension in chain hanging down = mg = 12 N (g=10 m/s^2)
Force required = Tension
Displacement = 0.6 m (part of chain hanging comes up)
W= Force * Displacement = 12 * 0.6 = 7.2 J
WORK DONE = 7.2 J.
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