A uniform chain of length land mass m overhangs a smooth table with
3rd part hanging. Potential energy of chain taking table as reference level, is
Answers
A uniform chain of length (l) and mass (m) overhangs a smooth table with its two thirds part lying on the table. What is the kinetic energy of the chain as it completely slips off the table?
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What we have to do here is to simply apply work-energy theorem on the chain. Work done by all the forces acting on the chain in any time interval must be equal to change in kinetic energy of it in the same interval. Following two forces act on the chain:
Gravity (applied by earth)
Normal Reaction (applied by surface of table)
Note that since the table is smooth (as stated in the problem) friction will be absent. Let's now find works done by gravity and normal force.
Since gravitational force is conservative in nature work done by it on the chain can be found as, W = -ΔGPE
where GPE stands for gravitational potential energy.
Also work done by normal reaction on the chain = 0 as the chain slips along a direction perpendicular to the normal reaction.
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