Question

A uniform chain of mass 10 kg and length 10 m is hanging on two smooth pulley in equilibrium such that each vertical part have length 3m. Find tension at
the mid point of string A between the pulleys (Neglect the length of string on the pulley) :-
M
А
30 N​

Answer 1

Answer:

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Answer 2

Answer:

The tension at the midpoint of string A is 50N.

Explanation:

• The chain is in equilibrium, so tension at both points A and B will be the same, consider it as t,

t = m× l

t = 10×3

t = 30N

• For string A, at the midpoint, there is no force to balance the weight, so the component of tension will balance its weight,

It will be equal to 30N + 20N = 50 N