A uniform chain of mass 10 kg and length 10 m is hanging on two smooth pulley in equilibrium such that each vertical part have length 3m. Find tension at the mid point of string A between the pulleys (Neglect the length of string on the pulley)
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A uniform rope of length 20 m and mass 20 kg is shown in the figure. The hanging part on each side is 6 m. C is the middle point of ACB part of rope. Find the tension at point C. Assume that the rope is in equilibrium.
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Since, this body is in equilibrium tension at point A and B will be same, let it be T.
Then,
T=6g
T=60N
For tension at point C consider its half part,
Since, there is no force to balance the weight 50 a component of tension in each element will balance its weight.
Total tension=60N+40N
T=100N
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