Question

A uniform chain of
of mass 4 kg and length 2m is kept on table such that 3/10* of the chain hangs freely from
the edge of the table. How much
work has to be done
pulling
the entire chain on the table ?
(A) 7.2J
(B) 120J
(C) 1200J
(D) 3.6J​

Answer 1

Given:-

• Length of chain kept on table = 2m.
• Length of chain hangs freely = 60cm→ 0.6m

To Find:-

• The work done in Pulling the entire Chain on the table.

Formulae used:-

• Potential energy ( Work done ) = mgh

Where,

• m = Mass
• g = Acceleration due to gravity.
• h = Height

Now,

$\sf{\dfrac{m}{l}}$

→ Mass Per length = $\sf{\dfrac{4}{2}}$

→ Mass Per length = 2kg/m.

So,

→ Mass of chain lying freely = 0.6 × 2

→ Mass of chain lying freely = 1.2kg

Therefore,

→ The center of mass of Hanging Part = 0.3m.

Hence,

$\text{Work~done~on~Pulling~the~Chain~on~the~table=~mgh}$

→ Work Done = 1.2 × 10 × 0.3 → 3.6J.

→ Work Done = 1.2 × 10 × 0.3 → 3.6J.Hence, The Work done is 3.6J.

Answer 2

Explanation:

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