Question

A uniform circular disc of mass 2.0 kg and radius 20 cm is rotated about one of its diameters. Find angular speed about this diameter if angular momentum is 0.2 kgm2 s –1.
Give explaination in 40-60 words.​

Answer 1

Answer:-

• Mass=2kg
• Radius=20cm
• Angular momentum=0.2kgm^2s^{-2}
• Angular velocity=$\omega$

We know

$\boxed{\sf Angular\:Momentum=Mass\times Radius\times \omega}$

$\\ \sf\longmapsto 0.2=2\times 20\times \omega$

$\\ \sf\longmapsto \omega=\dfrac{0.2}{2\times 20}$

$\\ \sf\longmapsto \omega=\dfrac{0.2}{40}$

$\\ \sf\longmapsto \omega=0.005rad/s$

Answer 2

Answer:

mass=2kg

radius=20x10^-2 m =0.2 m

angular momentum= 0.2 kg m2 s-1

Explanation:

angular momentum = mass x radius x angular velocity

0.2 = 2 x 0.2 x w

w = 0.2/2 x 0.2

w = 0.2/0.4

w= 0.5 rad/ s