Question

A uniform circular disc of mass m is set rolling on a smooth horizontal table with a uniform linear velocity.Find the total kinetic energy of the disc

Answer 1

Answer:

The answer will be 3/2mv^2

Explanation:

According to the problem the mass of the disc is m which is rotating on a table with a velocity

Now let the velocity be v

Therefore, v = rω or. ω = v/r

Therefore the total kinetic energy of the disc = rotational energy + translational energy

=1/2mv^2 + 1/2Iω^2

Now I = mr^/2

Therefore, Total kinetic energy = 1/2mv^2 + 1/2 x mr^/2 x v^2/r^2 = 3/2mv^2

Answer 2

Answer:

The answer will be 3/2mv^2

Explanation:

According to the problem the mass of the disc is m which is rotating on a table with a velocity

Now let the velocity be v

Therefore, v = rω or. ω = v/r

Therefore the total kinetic energy of the disc = rotational energy + translational energy

=1/2mv^2 + 1/2Iω^2

Now I = mr^/2

Therefore, Total kinetic energy = 1/2mv^2 + 1/2 x mr^/2 x v^2/r^2 = 3/2mv^2

Hope it helps you

Mark me brainlist please