Question

a uniform circular path of width 2.5 m is laid out side a circular park of radius 56cm find the cost of levelling the path at the rate of ruppees 5 per metre square (take π= 3.14​

Answer 1

Answer: Rs.4494.125

Step by step explanation:

Given,

=> Radius of inner circle = 56 m

=> width of the circular path = 2.5 m

=> Cost of leveling 1 square meter = Rs. 5

Area of circle = πr^2

▪️ We have to find area of Inner circle.

So,

➡️ 3.14×56^2

➡️ 9847.04m^2

Now, we will have to find Radius of outer circle.

So,

Radius of the outer circle = inner radius +width = 56+2.5 =58.5 m

▪️ Area of outer circle => 3.14×58.5^2

▪️ Area of outer circle => 10745.865 m^2

◼️ Area of path = Area of outer circle - Area of inner circle

=> 10745.865 - 9847.04m^2

=> 898.825 m^2

Given that, Cost of leveling 1 square meter = Rs. 5

=> cost of leveling 898.825 square meter = 898.825 *5 = Rs.4494.125

⬛️ Therefore, cost of leveling the path is Rs.4494.125

Answer 2

ANSWER:--------

Step-by-step

Radius of inner circle = 56 mArea of circle = Area of inner circle =                                 = The

{width of the circular path is 2.5 m So, the radius of the outer circle = inner radius +width = 56+2.5 =58.5 mArea of outer circle = }

                              ={ So, area of path = Area of outer circle - Area of inner circle }                                                   = {Now , Cost of leveling 1 square meter = Rs. 5So, cost of leveling 898.825 square meter = 898.825 *5 = Rs.4494.125}

{Hence the cost of leveling the path is Rs. 4494.125 }

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