Question

a uniform circular path of width 2.5 m is laid outside a circular park of radius 56cm. find the cost of levelling the path at the rate of rs.5 per m take py =3.14

Answer 1

Answer:

Step-by-step explanation:

= 48 + 4 = 52m  

r = 48m  

A = π(R+r)(R−r)

= 3.14 (52 + 48)(52 - 48)  

=3.14(100)(4) = 1256m2

Answer 2

Answer: Rs.4494.125

Step by step explanation:

Given,

Radius of inner circle = 56 m

Width of the circular path = 2.5 m

Cost of leveling 1 square meter = Rs. 5

To find: We have to find cost of leveling of Circular park.

Area of circle = πr²

Area of Inner circle = 3.14×56²

                                = 9847.04m²

Radius of the outer circle = inner radius +width = 56+2.5 =58.5 m

Area of outer circle =  3.14×58.5^2

                                 =  10745.865 m^2

Area of path = Area of outer circle - Area of inner circle

=> 10745.865 - 9847.04m²

=> 898.825 m²

Given that, Cost of leveling 1 square meter = Rs. 5

Cost of leveling 898.825 square meter       = 898.825 *5

                                                                       = Rs.4494.125

Therefore, cost of leveling the path is Rs.4494.125