a uniform circular path of width 2.5 m is laid outside a circular park of radius 56cm. find the cost of levelling the path at the rate of rs.5 per m take py =3.14
Answers
Answer:
Step-by-step explanation:
= 48 + 4 = 52m
r = 48m
A = π(R+r)(R−r)
= 3.14 (52 + 48)(52 - 48)
=3.14(100)(4) = 1256m2
Answer: Rs.4494.125
Step by step explanation:
Given,
Radius of inner circle = 56 m
Width of the circular path = 2.5 m
Cost of leveling 1 square meter = Rs. 5
To find: We have to find cost of leveling of Circular park.
Area of circle = πr²
Area of Inner circle = 3.14×56²
= 9847.04m²
Radius of the outer circle = inner radius +width = 56+2.5 =58.5 m
Area of outer circle = 3.14×58.5^2
= 10745.865 m^2
Area of path = Area of outer circle - Area of inner circle
=> 10745.865 - 9847.04m²
=> 898.825 m²
Given that, Cost of leveling 1 square meter = Rs. 5
Cost of leveling 898.825 square meter = 898.825 *5
= Rs.4494.125
Therefore, cost of leveling the path is Rs.4494.125