Question

a uniform circular plate of radius 2R has a circular hole of radius R cut out of it.The centet C of the smaller circle is a distance 0.807? from the center C of the larger circle.What is the position of the center of mass of the plate?

Answer 1

Answer:

Explanation:

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Answer 2

Thus the centre of mass is  - 0.27 R

Explanation:

Surface mass density = σ

σ  = M / π (2R)^2 = M / 4πR^2

Mass of the removed circle = πR^2 x v

πR^2 x M / 4πR^2

M' = M / 4

Centre of mass = Mx1 -  Mx2 / M1 - M2

Centre of mass  = Mxo - M / 4 x 0.80 R / 3 M / 4

Centre of mass  = = 0.80 R / 3

Centre of mass  = - 0.27 R

Thus the centre of mass is  - 0.27 R