Question

A uniform conducting wire abc has a mass of 10g. A current of 2 ampere flows through it the wire is kept in a uniform magnetic field

Answer 1

Answer:

The acceleration will be 6B m/s^2

Explanation:

According to the problem ab and bc are equivalent with ac

Therefore, ac = √ (5)^2  - 4^2 = 3 cm = 3 x 20^(-2) m

Now let the force given on ac is f

f = Blℓ sinθ

here B is the magnetic field I is current

I is given as 2 A

Therefore

f =  2 x B x 3 x 10^(-2) x sin 90

  = B x 6 x 10^(-2)  N

Therefore the acceleration will be  a = f/m =  B x 6 x 10^(-2) /10 x 10^(-3) = 6Bm/s^2