A uniform cube of edge length 5 cm and mass 5kg is kept on a table top.Find pressure due to the cube on the table top on the portion where the cube touches the table top.
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weight = 5×10 =50N
area = 0.05^2 = 0.0025 m^2
pressure= 50/0.0025 = 20000pa = 20kpa
area = 0.05^2 = 0.0025 m^2
pressure= 50/0.0025 = 20000pa = 20kpa
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Answer:
4X10^8 N/m²
Explanation:
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