A uniform cylindrical container is half filled with water. the height of the cylinder is twice its diameter. the cylinder is gradually tilted until the water touches the brim. at ts instant, the container is inclined at
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It is given that height of the cylinder is twice that of its diameter.
Meaning if height = h, the diameter will be h / 2
Using this we can imagine that when we tilt the cylinder until the water touches the brim.
The height falls to half of its original height since the it was initially half filled.
Using formula
Sin x(angle of tilt) = D / h
D = 1/2h
Sin x = 1/2 ÷ 1 = 1/2
We get, sin x = 1/2
Sin⁻¹ 0.5 = 30°
x = 30 degrees
Meaning if height = h, the diameter will be h / 2
Using this we can imagine that when we tilt the cylinder until the water touches the brim.
The height falls to half of its original height since the it was initially half filled.
Using formula
Sin x(angle of tilt) = D / h
D = 1/2h
Sin x = 1/2 ÷ 1 = 1/2
We get, sin x = 1/2
Sin⁻¹ 0.5 = 30°
x = 30 degrees
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5
Answer:
Explanation:
It is given that height of the cylinder is twice that of its diameter.
Meaning if height = h, the diameter will be h / 2
Using this we can imagine that when we tilt the cylinder until the water touches the brim.
The height falls to half of its original height since the it was initially half filled.
Using formula
Sin x(angle of tilt) = D / h
D = 1/2h
Sin x = 1/2 ÷ 1 = 1/2
We get, sin x = 1/2
Sin⁻¹ 0.5 = 30°
x = 30 degrees
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