A uniform cylindrical ice berg of density 0.9g/cm Noats in wate of
density 100kg/m'. The lenght of the ice berg is 50cm, The length of the se
berg above the water surnce is
2. 10 cm
3. 5cm
4. 20 cm
1. 25 cm
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Answer:
V be the volume of the iceberg, x be the volume out of seawater.
The iceberg is floating in sea water then
Vρ
ice
g=(V−x)ρ
seawater
g
or V×0.9×g=(V−x)1.1gor0.9V=1.1V−1.1x
0.2V=1.1x
∴
V
x
=
1.1
0.2
Percentage of fraction of the volume of iceberg above the level of sea water
v
x
×100=
1.1
0.2
×100=18%
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