Question

A uniform electric field of 10 NC-1 exists in the vertically downward direction. What is the increase in the electric potential asonegoes up through a height of 300 cm?
(a) 15 V
(b) 30 V
(C) 45V
(d) None of these​

Answer 1

Answer:

d....as all three r wrong and cannot be

Answer 2

Explanation:

Given values in the question :

E = 10 n/c

E is A uniform electric field

Change in height, ds = 50 cm

"ds" is a height

Converting height centimeter to meter :

(i.e ) One centimeter is one-hundred of a metre.

It would take 100 cm long to equal a single meter in length .

r=\frac{50}{100}=0.5 \mathrm{m}r=

100

50

=0.5m

Change in electric potential, dv = E.ds

dv = 10×0.5

dv = 5 v

Thus, 5V raise the electric potential as one climbs up to 50 cm in height.

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