Question

A uniform electric field off 100 n/c exists in vertically upward direction the decrease in v as one goes up through a height of 20 cm is

Answer 1

Given:

A uniform electric field off 100 N/C exists in vertically upward direction.

To find:

Decrease in electrostatic potential when a charge goes after through a height of 20 cm ?

Calculation:

So, the general expression relative electrostatic field intensity and electrostatic potential is as follows:

$\boxed{ \bold{ \therefore \: \Delta V = - E \times \Delta l}}$

• Here ∆V represents the change in potential, E represents the electrostatic field intensity and ∆l represents the displacement of the charge.

Putting available values in SI units:

$\sf \implies\: \Delta V = - (100 \times \dfrac{20}{100} )$

$\sf \implies\: \Delta V = - 20 \: volt$

So, the decrease in Electrostatic Potential for that charge will be 20 volt.