Question

A uniform field of magnitude
E = 2000NC-lis directed 0 = 37°below
the horizontal as shown. The potential
difference between the points P and R is​

Answer 1

VP = 580 V

Explanation:

Given: E = 2000 NC−1 , θ=37∘ , VR = 500 V

Solution:

Δl = PR = 5cm = 5/100 m

VR − VP = E→.Δl→ = −EdlCosθ

= − (2000 NC−1)(5/100) Cos37∘

VR − VP = −80 V

Hence VP − VR = E→.Δl→ = 80 V

As VP − VR = 80 V and given that VR = 500 V.

VP = VR + 80 V = 500 V + 80 V = 580 V

Answer 2

Answer:

$\cos(37 )= 0.79$

Explanation:

Thank you.