A uniform flexiable chain of mass 2 kg is hanging.what work should be done externally to change its positions .(length of chain is 4m and take ģ as 10m/s square
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Mass of the chain lying freely from the table=M
L=4kg× 20.6 =1.2kg
The distance of center of mass of chain from the table= 21 ×0.6m=0.3m
Thus the work done in pulling the chain=mgh=1.2×10×0.3J=3.6J
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