Question

A uniform half metre rule is freely pivoted at 15cm mark and it balance horizontally when a body of mass 40g is hung from 2cm mark . calculate the mass of the object placed 10cm to the end of the ruler

Answer 1

Let the weight of the half metre rule be x gf and it acts at the 25 cm mark (centre of gravity).
Now,
•Acticlockwise moment = x * 4
•Clockwise moment = 20 * 21
In equilibrium,
Anticlockwise moment = Clockwise moment
•4x = 20*21
x = 105 gf.
Thus, the weight of the metre rule is 105 gf.
•We know, one gf is the force acting on the body of mass 1 grams, thus mass of the body is 105 grams.



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